Proof of the Chain Rule

Considering a composite function C(x)=f(g(x)), we write a difference quotient for the derivative: C'(x)=lim(h->0)(f(g(x+h))-f(g(x)))/h. Now let’s define k=g(x+h)-g(x) so g(x+h)=g(x)+k. Then we substitute that into our difference quotient, giving lim(h->0)(f(g(x)+k)-f(g(x)))/h. We multiply both the numerator and denominator by k/h to get lim(h->0)(k/h)(f(g(x)+k)-f(g(x)))/k). Clearly lim(h->0)k=0 from the definition of k, so we can consider our limit to be a lim(k->0). Now we notice that the second factor in the limit is a difference quotient that gives f'(g(x)), so we now know that C'(x)=f'(g(x))lim(k->0)(k/h).

To find the value of lim(k->0)(k/h), we use the difference quotient for g'(x)=lim(h->0)(g(x+h)-g(x))/h), but the numerator of that is how we defined k (noting our assumption that g(x) is differentiable). Therefore g'(x)=lim(k->0)(k/h) and we have C'(x)=f'(g(x))g'(x). This is the chain rule.

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